f(a+h)=4x^2+4x-5

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Solution for f(a+h)=4x^2+4x-5 equation:


Simplifying
f(a + h) = 4x2 + 4x + -5
(a * f + h * f) = 4x2 + 4x + -5
(af + fh) = 4x2 + 4x + -5

Reorder the terms:
af + fh = -5 + 4x + 4x2

Solving
af + fh = -5 + 4x + 4x2

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-1fh' to each side of the equation.
af + fh + -1fh = -5 + 4x + -1fh + 4x2

Combine like terms: fh + -1fh = 0
af + 0 = -5 + 4x + -1fh + 4x2
af = -5 + 4x + -1fh + 4x2

Reorder the terms:
af = -5 + -1fh + 4x + 4x2

Divide each side by 'f'.
a = -5f-1 + -1h + 4f-1x + 4f-1x2

Simplifying
a = -5f-1 + -1h + 4f-1x + 4f-1x2

Reorder the terms:
a = -5f-1 + 4f-1x + 4f-1x2 + -1h

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